find the coordinates of the midpoint of HX. H(-1,3), X(7,-1)

find the coordinates of the midpoint of HX. H(-1,3), X(7,-1)

$$\vec{H}=\left(\begin{array}{rcl} -1\\3 \end{array} \right) \quad \vec{X}=\left(\begin{array}{rcl} 7\\-1 \end{array} \right) \quad \vec{midpoint}=\dfrac{\vec{H}+\vec{X}} {2}$$

$$\\\vec{midpoint}=\dfrac{ \left(\begin{array}{rcl} -1\\3 \end{array} \right) + \left(\begin{array}{rcl} 7\\-1 \end{array} \right) } {2} = \dfrac{ \left(\begin{array}{rcl} -1+7\\3-1 \end{array} \right) } {2} = \dfrac{ \left(\begin{array}{rcl} 6\\2\end{array} \right) } {2} = \left(\begin{array}{rcl} 3\\1\end{array} \right)$$

To find the midpoint   .... add the x coordinates and divide by 2   ...then, add the y coordinates and divide by 2.......the first result will be the x coordinate of the midpoint and the second result will give you the y coordinate of the midpoint....