+4473 f(x)=2x+5 & g(x)=x^2-3x+2
56) -3f(x)*g(x)
-3(2x+5)*(x^2-3x+2)
(-6x-15)*(x^2-3x+2)
-6x^3+18x^2-12x-15x^2+45x-30
-6x^3+3x^2+33x-30
There are no restrictions to the x values as seen above...therefore, the domain is all real numbers.
58) 5f(x)/g(x)
5(2x+5)/(x^2-3x+2)
10x+25/(x^2-3x+2)
Here, note that we have a polynomial in the denominator...therefore, we have to consider what values make the denominator equal to 0, which will ultimately produce something that is undefined...
(x^2-3x+2) = (x-2)(x-1)...set both of these equal to 0 -->
(x-2) = 0 & (x-1) = 0
x = 2 and 1...now we know that x cannot equal 2 and 1...so our domain is restricted to all real numbers except for x = 2 & x = 1.
+4473 f(x)=2x+5 & g(x)=x^2-3x+2
56) -3f(x)*g(x)
-3(2x+5)*(x^2-3x+2)
(-6x-15)*(x^2-3x+2)
-6x^3+18x^2-12x-15x^2+45x-30
-6x^3+3x^2+33x-30
There are no restrictions to the x values as seen above...therefore, the domain is all real numbers.
58) 5f(x)/g(x)
5(2x+5)/(x^2-3x+2)
10x+25/(x^2-3x+2)
Here, note that we have a polynomial in the denominator...therefore, we have to consider what values make the denominator equal to 0, which will ultimately produce something that is undefined...
(x^2-3x+2) = (x-2)(x-1)...set both of these equal to 0 -->
(x-2) = 0 & (x-1) = 0
x = 2 and 1...now we know that x cannot equal 2 and 1...so our domain is restricted to all real numbers except for x = 2 & x = 1.
