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Given the function

invf1.jpg

(a) Find the domain of  f(x).   

(b) Find the range of  f(x).

zandaleebailey  Mar 4, 2015

Best Answer 

 #3
avatar+90001 
+10

The domain of this function is all x's except x =3......that would make the denominator 0

This function has a horizontal asymptote at y = 1

Thus, the range is (-∞, 1) u (1,∞)

Here's a graph......https://www.desmos.com/calculator/gxycvvat1h

 

CPhill  Mar 4, 2015
 #1
avatar+93664 
0

Where is the pic?

Melody  Mar 4, 2015
 #2
avatar
0

The picture is f(x)= x+1/x-3

Guest Mar 4, 2015
 #3
avatar+90001 
+10
Best Answer

The domain of this function is all x's except x =3......that would make the denominator 0

This function has a horizontal asymptote at y = 1

Thus, the range is (-∞, 1) u (1,∞)

Here's a graph......https://www.desmos.com/calculator/gxycvvat1h

 

CPhill  Mar 4, 2015
 #4
avatar+93664 
+5

CPhill has probably interpreted this as you intended but it really needed brackets because

 

$$x+1/x-3 = x+\frac{1}{x}-3$$

 

Remember that you do division BEFORE you do addition or subtraction!

 

$$(x+1)/(x-3) = \frac{x+1}{x-3}$$

Melody  Mar 4, 2015

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