$$\\(x-h)^2=4a(y-k) \qquad where \;\;h=0\;\;and\;\;k=0\\\\ x^2=4ay\\\\ $The directric is above the vertex so the parabola is concave down$\\ $so a is negaive$\\\\ a=-1/22\\\\\\ x^2=\frac{-4y}{22}\\\\ x^2=\frac{-2y}{11}\\\\ or\\\\ 11x^2+2y=0$$
$$\\(x-h)^2=4a(y-k) \qquad where \;\;h=0\;\;and\;\;k=0\\\\ x^2=4ay\\\\ $The directric is above the vertex so the parabola is concave down$\\ $so a is negaive$\\\\ a=-1/22\\\\\\ x^2=\frac{-4y}{22}\\\\ x^2=\frac{-2y}{11}\\\\ or\\\\ 11x^2+2y=0$$