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Find the equation for the parabola that has its vertex at the origin and has directrix at y=1/22. equation is______

 Jun 13, 2015

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 #1
avatar+118667 
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$$\\(x-h)^2=4a(y-k) \qquad where \;\;h=0\;\;and\;\;k=0\\\\
x^2=4ay\\\\
$The directric is above the vertex so the parabola is concave down$\\
$so a is negaive$\\\\
a=-1/22\\\\\\
x^2=\frac{-4y}{22}\\\\
x^2=\frac{-2y}{11}\\\\
or\\\\
11x^2+2y=0$$

.
 Jun 13, 2015
 #1
avatar+118667 
+5
Best Answer

$$\\(x-h)^2=4a(y-k) \qquad where \;\;h=0\;\;and\;\;k=0\\\\
x^2=4ay\\\\
$The directric is above the vertex so the parabola is concave down$\\
$so a is negaive$\\\\
a=-1/22\\\\\\
x^2=\frac{-4y}{22}\\\\
x^2=\frac{-2y}{11}\\\\
or\\\\
11x^2+2y=0$$

Melody Jun 13, 2015

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