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# Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)

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Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)

A)y = 6x - 14

B)y = 6x + 14

C)y = -6x - 14

D)y = 1/6x - 14

Feb 13, 2018

#1
+7598
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First we need to find the slope of the line...

y - 5  =  6x - 10

Add  5  to both sides of the equation.

y  =  6x - 5           Now that this is in slope-intercept form, we can see that its slope is  6 .

The slope of a line that is parallel to this will also be  6 .

Using the point  (4, 10)  and a slope of  6  , the equation of our line in point-slope form is...

y - 10   =   6(x - 4)

Distribute the  6  to both terms in parenthesees.

y - 10   =   6x - 24

Add  10  to both sides of the equation.

y   =   6x - 14          This is the equation in slope-intercept form.

Feb 13, 2018
#2
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Alternatively

6x - y + k = 0 then substitute (4,10)

ie k = -14

therefore equation becomes 6x - y -14 = 0 ie y = 6x - 14

Feb 13, 2018
#3
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Hey! I like that way!

hectictar  Feb 13, 2018
#4
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Thanks.....it's yours

Feb 13, 2018
edited by Guest  Feb 13, 2018