Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)

A)y = 6x - 14

B)y = 6x + 14

C)y = -6x - 14

D)y = 1/6x - 14

Guest Feb 13, 2018

#1**+1 **

First we need to find the slope of the line...

y - 5 = 6x - 10

Add 5 to both sides of the equation.

y = 6x - 5 Now that this is in slope-intercept form, we can see that its slope is 6 .

The slope of a line that is parallel to this will also be 6 .

Using the point (4, 10) and a slope of 6 , the equation of our line in point-slope form is...

y - 10 = 6(x - 4)

Distribute the 6 to both terms in parenthesees.

y - 10 = 6x - 24

Add 10 to both sides of the equation.

y = 6x - 14 This is the equation in slope-intercept form.

hectictar
Feb 13, 2018