Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)
A)y = 6x - 14
B)y = 6x + 14
C)y = -6x - 14
D)y = 1/6x - 14
First we need to find the slope of the line...
y - 5 = 6x - 10
Add 5 to both sides of the equation.
y = 6x - 5 Now that this is in slope-intercept form, we can see that its slope is 6 .
The slope of a line that is parallel to this will also be 6 .
Using the point (4, 10) and a slope of 6 , the equation of our line in point-slope form is...
y - 10 = 6(x - 4)
Distribute the 6 to both terms in parenthesees.
y - 10 = 6x - 24
Add 10 to both sides of the equation.
y = 6x - 14 This is the equation in slope-intercept form.
6x - y + k = 0 then substitute (4,10)
ie k = -14
therefore equation becomes 6x - y -14 = 0 ie y = 6x - 14