We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

+0

# Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)

+1
1119
4

Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)

A)y = 6x - 14

B)y = 6x + 14

C)y = -6x - 14

D)y = 1/6x - 14

Feb 13, 2018

### 4+0 Answers

#1
+1

First we need to find the slope of the line...

y - 5  =  6x - 10

Add  5  to both sides of the equation.

y  =  6x - 5           Now that this is in slope-intercept form, we can see that its slope is  6 .

The slope of a line that is parallel to this will also be  6 .

Using the point  (4, 10)  and a slope of  6  , the equation of our line in point-slope form is...

y - 10   =   6(x - 4)

Distribute the  6  to both terms in parenthesees.

y - 10   =   6x - 24

Add  10  to both sides of the equation.

y   =   6x - 14          This is the equation in slope-intercept form.

Feb 13, 2018
#2
+2

Alternatively

6x - y + k = 0 then substitute (4,10)

ie k = -14

therefore equation becomes 6x - y -14 = 0 ie y = 6x - 14

Feb 13, 2018
#3
+2

Hey! I like that way! hectictar  Feb 13, 2018
#4
+2 Thanks.....it's yours

Feb 13, 2018
edited by Guest  Feb 13, 2018