+647 Find the equation of the line passing through the points (-3, -16) and (4,5). Enter your answer in "y=mx+b" form.
+9479 First let's find the slope between these two points.
slope \(=\,\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{5-(-16)}{4-(-3)}\,=\,\frac{5+16}{4+3}\,=\,\frac{21}{7}\) = 3
Using a slope of 3 and the point (4, 5) , the equation of the line in point-slope form is
y - 5 = 3(x - 4) Distribute the 3 .
y - 5 = 3x - 12 Add 5 to both sides.
y = 3x - 7 
+9479 First let's find the slope between these two points.
slope \(=\,\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{5-(-16)}{4-(-3)}\,=\,\frac{5+16}{4+3}\,=\,\frac{21}{7}\) = 3
Using a slope of 3 and the point (4, 5) , the equation of the line in point-slope form is
y - 5 = 3(x - 4) Distribute the 3 .
y - 5 = 3x - 12 Add 5 to both sides.
y = 3x - 7
