We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
304
1
avatar+153 

Find the equation of the line that passes through the point whose coordinates are

(-1,-3) and has a slope of -3.

 Nov 3, 2017

Best Answer 

 #1
avatar+7354 
+1

slope  =  [y2 - y1] / [x2 - x1]

 

Using the points  (-1, -3)  and  (x, y)  and a slope of  -3 , we have

 

-3  =  [y - -3] / [x - -1]

 

-3  =  [y + 3] / [x + 1]           To get this into slope-intercept form, multiply both sides by  x + 1 .

 

-3[ x + 1 ]  =  y + 3

 

-3x - 3  =  y + 3                   Subtract  3  from both sides of the equation.

 

-3x - 6  =  y

 

y  =  -3x - 6

 Nov 3, 2017
 #1
avatar+7354 
+1
Best Answer

slope  =  [y2 - y1] / [x2 - x1]

 

Using the points  (-1, -3)  and  (x, y)  and a slope of  -3 , we have

 

-3  =  [y - -3] / [x - -1]

 

-3  =  [y + 3] / [x + 1]           To get this into slope-intercept form, multiply both sides by  x + 1 .

 

-3[ x + 1 ]  =  y + 3

 

-3x - 3  =  y + 3                   Subtract  3  from both sides of the equation.

 

-3x - 6  =  y

 

y  =  -3x - 6

hectictar Nov 3, 2017

19 Online Users