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Find the equation of the line that passes through the point whose coordinates are

(-1,-3) and has a slope of -3.

Tiffybean  Nov 3, 2017

Best Answer 

 #1
avatar+5256 
+1

slope  =  [y2 - y1] / [x2 - x1]

 

Using the points  (-1, -3)  and  (x, y)  and a slope of  -3 , we have

 

-3  =  [y - -3] / [x - -1]

 

-3  =  [y + 3] / [x + 1]           To get this into slope-intercept form, multiply both sides by  x + 1 .

 

-3[ x + 1 ]  =  y + 3

 

-3x - 3  =  y + 3                   Subtract  3  from both sides of the equation.

 

-3x - 6  =  y

 

y  =  -3x - 6

hectictar  Nov 3, 2017
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1+0 Answers

 #1
avatar+5256 
+1
Best Answer

slope  =  [y2 - y1] / [x2 - x1]

 

Using the points  (-1, -3)  and  (x, y)  and a slope of  -3 , we have

 

-3  =  [y - -3] / [x - -1]

 

-3  =  [y + 3] / [x + 1]           To get this into slope-intercept form, multiply both sides by  x + 1 .

 

-3[ x + 1 ]  =  y + 3

 

-3x - 3  =  y + 3                   Subtract  3  from both sides of the equation.

 

-3x - 6  =  y

 

y  =  -3x - 6

hectictar  Nov 3, 2017

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