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# Find the equation of the line that passes through the point whose coordinates are

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Find the equation of the line that passes through the point whose coordinates are

(-1,-3) and has a slope of -3.

Nov 3, 2017

#1
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slope  =  [y2 - y1] / [x2 - x1]

Using the points  (-1, -3)  and  (x, y)  and a slope of  -3 , we have

-3  =  [y - -3] / [x - -1]

-3  =  [y + 3] / [x + 1]           To get this into slope-intercept form, multiply both sides by  x + 1 .

-3[ x + 1 ]  =  y + 3

-3x - 3  =  y + 3                   Subtract  3  from both sides of the equation.

-3x - 6  =  y

y  =  -3x - 6

Nov 3, 2017

#1
+1

slope  =  [y2 - y1] / [x2 - x1]

Using the points  (-1, -3)  and  (x, y)  and a slope of  -3 , we have

-3  =  [y - -3] / [x - -1]

-3  =  [y + 3] / [x + 1]           To get this into slope-intercept form, multiply both sides by  x + 1 .

-3[ x + 1 ]  =  y + 3

-3x - 3  =  y + 3                   Subtract  3  from both sides of the equation.

-3x - 6  =  y

y  =  -3x - 6

hectictar Nov 3, 2017