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# Find the equation of the line that passes through these two points:

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Find the equation of the line that passes through these two points:

(-6, -13) and (6, -1)

Nov 3, 2017

#1
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To find the slope of a line, the equation is $$\frac{y_2-y_1}{x_2-x_1}$$.

Plug in the point values.

$$\frac{-1+13}{6+6}$$

Simplify.

$$\frac{-1+13}{6+6}=\frac{12}{12}=1$$

So the slope is 1. Now use point-slope form, which is $$y-y_1=m(x-x_1)$$.

Now, it doesn't matter which point you plug in. I'll use (-6,-13).

$$y+13=1(x+6)$$

Distribute the 1.

$$y+13=x+6$$

Subtract the 13 from both sides.

$$y=x-7$$

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Nov 3, 2017

#1
+2

To find the slope of a line, the equation is $$\frac{y_2-y_1}{x_2-x_1}$$.

Plug in the point values.

$$\frac{-1+13}{6+6}$$

Simplify.

$$\frac{-1+13}{6+6}=\frac{12}{12}=1$$

So the slope is 1. Now use point-slope form, which is $$y-y_1=m(x-x_1)$$.

Now, it doesn't matter which point you plug in. I'll use (-6,-13).

$$y+13=1(x+6)$$

Distribute the 1.

$$y+13=x+6$$

Subtract the 13 from both sides.

$$y=x-7$$