Find the equation of the line that passes through these two points:
(-6, -13) and (6, -1)
To find the slope of a line, the equation is \(\frac{y_2-y_1}{x_2-x_1}\).
Plug in the point values.
\(\frac{-1+13}{6+6}\)
Simplify.
\(\frac{-1+13}{6+6}=\frac{12}{12}=1\)
So the slope is 1. Now use point-slope form, which is \(y-y_1=m(x-x_1)\).
Now, it doesn't matter which point you plug in. I'll use (-6,-13).
\(y+13=1(x+6)\)
Distribute the 1.
\(y+13=x+6\)
Subtract the 13 from both sides.
\(y=x-7\)
To find the slope of a line, the equation is \(\frac{y_2-y_1}{x_2-x_1}\).
Plug in the point values.
\(\frac{-1+13}{6+6}\)
Simplify.
\(\frac{-1+13}{6+6}=\frac{12}{12}=1\)
So the slope is 1. Now use point-slope form, which is \(y-y_1=m(x-x_1)\).
Now, it doesn't matter which point you plug in. I'll use (-6,-13).
\(y+13=1(x+6)\)
Distribute the 1.
\(y+13=x+6\)
Subtract the 13 from both sides.
\(y=x-7\)