Find the equation of the line that passes through these two points:

(-6, -13) and (6, -1)

Tiffybean
Nov 3, 2017

#1**+2 **

To find the slope of a line, the equation is \(\frac{y_2-y_1}{x_2-x_1}\).

Plug in the point values.

\(\frac{-1+13}{6+6}\)

Simplify.

\(\frac{-1+13}{6+6}=\frac{12}{12}=1\)

So the slope is 1. Now use point-slope form, which is \(y-y_1=m(x-x_1)\).

Now, it doesn't matter which point you plug in. I'll use (-6,-13).

\(y+13=1(x+6)\)

Distribute the 1.

\(y+13=x+6\)

Subtract the 13 from both sides.

\(y=x-7\)

AdamTaurus
Nov 3, 2017

#1**+2 **

Best Answer

To find the slope of a line, the equation is \(\frac{y_2-y_1}{x_2-x_1}\).

Plug in the point values.

\(\frac{-1+13}{6+6}\)

Simplify.

\(\frac{-1+13}{6+6}=\frac{12}{12}=1\)

So the slope is 1. Now use point-slope form, which is \(y-y_1=m(x-x_1)\).

Now, it doesn't matter which point you plug in. I'll use (-6,-13).

\(y+13=1(x+6)\)

Distribute the 1.

\(y+13=x+6\)

Subtract the 13 from both sides.

\(y=x-7\)

AdamTaurus
Nov 3, 2017