find the equation of the tangent line to at x=2

First:  find the y-value when x = 2:     y  =  16(2) - 12(2)² + 2  =  -14   --->   (2, -14)

 

Second:  in order to find the slope of the line, find the first derivative of y:

      y'  =  16 - 2·12x     --->     y'  =  16 - 24x

At x = 2   --->   y'  =  16 - 24·2  =  -32

 

You know have both the point and the slope at that point; use the point-slope form:

     y - -14  =  -32(x - 2)