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Find the exact value of

cot-1[tan(45°)]     and 

csc^-1[sec(150°)]

 Apr 14, 2016
 #1
avatar+129907 
0

cot-1  [tan 45°]  =

cot-1 [1]  =

45°

 

csc-1 [sec150°]  =

csc-1 [-2/sqrt(3)] =

-60°

 

 

 

cool cool cool

 Apr 14, 2016
 #2
avatar+157 
0

I have the answer for both of these problems
the first one:135°
the second one : -60°

Here is the work that is given to me which by the way I do not understand and maybe you will.
cot-1[tan(45°)] = cot-1(-1) from A S TC cot-1(-1)=135°

Please hellp !!!!!

ariannasofia1  Apr 14, 2016
 #3
avatar+129907 
0

Arianna....the   tan(45°)  = 1  , not  -1

 

So

 

cot-1 [ tan (45°) ] =

cot-1 [1]  =

45°

 Apr 14, 2016
 #4
avatar+157 
0

I'm telling you this problem was already answered for me , I am expected to she the step by step process that leads the answer to be 135°
I was given a few steps which I do not understand ... But the answer of the problem in 135°

ariannasofia1  Apr 14, 2016
 #5
avatar+129907 
0

Here's the answer.....straight from WolframAlpha.......

 

 

It agrees perfectly with mine.....!!!!!

 

 

cool cool cool

 Apr 14, 2016
 #6
avatar+157 
0

I realize now that I wrote the question wrong  crying
cot-1[tan(-45)]
And even though I made it negative the answer did not change !

ariannasofia1  Apr 14, 2016
 #7
avatar+129907 
0

cot-1 [ tan (-45°) ]

 

tan(-45°)  = -1   .......so......

 

 

cot-1 [ -1]   =  135°

 

 

cool cool cool

 Apr 14, 2016

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