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find the family of quadratic functions (in simplest form) with roots at 2 plus/minus 3 root 5

 Aug 8, 2014

Best Answer 

 #2
avatar+4473 
+5

The "a" is just there like a constant to create variations of the graph.

 Aug 8, 2014
 #1
avatar+104963 
+5

So we have......

[x - (3√5 + 2)] * [x + (3√5 - 2)] = 0

x^2 - (3√5 + 2)x + (3√5 - 2)x - [ 45 - 4] = 0

x^2 - 4x - 41 = 0

I'm not exactly sure what you mean by "family,' but any multiples of this function would produce the same roots.

Anyone else have other approaches/ideas ???

Am I missing something???

 

 Aug 8, 2014
 #2
avatar+4473 
+5
Best Answer

The "a" is just there like a constant to create variations of the graph.

AzizHusain Aug 8, 2014
 #3
avatar+104963 
0

Thanks, Aziz.....I needed to put the "a" in there to indicate "multiples" or "family"

 

 Aug 8, 2014

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