Find the Fourth term of (6x+5)^5
I always am confused with these because I never know which end I am supposed to start from.
I guess there is some convention that I can never remember.
The coefficients for a power of 5 are 5C0, 5C1, 5C3, 5C4, 5C5 and these are 1,5, 10, 5,1
So, depending on which end you start from, the forth one is either
5∗(6x)4∗51=5∗64x4∗5=25∗1296∗x4=32400x4or5∗54∗(6x)1=55∗6x=18750x