Hello there; sorry for not publishing for so long, and yeah I know you missed me
Anyway, let me skip to the math problem:
In a Parliament, 30 MPs are divided in two parties, called the Party A and the Party B (I have so much imagination when it comes to finding names for things).
The A-ists then tell the B-ists:
"If one of you changes and join in our Party, we'll have twice as much seats as you in the Parliament!"
How many members are there in the Party A at the moment?
PS: I already know the answer; this is just some "brain food".
Let the number of members in "A" = N.......then the number of members of "B" = 30 - N
And we know that
A + 1 = 2 [ B - 1 ] or
N + 1 = 2 [ (30 - N) - 1] simplify
N + 1 = 2 [ 29 - N ]
N + 1 = 58 - 2N add 2N to both sides, subtract 1 from each side
3N = 57 divide both sides by 3
N = 19 = number in "A" and 30 - N = 11 = number in "B"
Proof : If one more member leaves "B" and joins "A"...."A" will have 20 members and "B" will have 10 and "A" will have twice as many members as "B"
That's right:
(and yeah, I still give those brownie pictures for right answers).