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avatar+870 

Hello there; sorry for not publishing for so long, and yeah I know you missed me laugh

 

Anyway, let me skip to the math problem:

 

In a Parliament, 30 MPs are divided in two parties, called the Party A and the Party B (I have so much imagination when it comes to finding names for things).

The A-ists then tell the B-ists:

"If one of you changes and join in our Party, we'll have twice as much seats as you in the Parliament!"

 

How many members are there in the Party A at the moment?

 

PS: I already know the answer; this is just some "brain food".

 Dec 17, 2016
 #1
avatar+129852 
0

Let the number of members in "A"  = N.......then the number of members of "B"  = 30 - N

 

And we know that

 

A + 1   =  2 [ B - 1 ]    or

 

N + 1  = 2 [ (30 - N) - 1]    simplify

 

N + 1  = 2 [ 29 - N ]

 

N + 1   = 58 - 2N     add 2N to both sides, subtract 1 from each side

 

3N  = 57      divide both sides by 3

 

N  = 19 = number in "A"    and 30 - N    = 11  =  number in "B"

 

Proof : If one more member leaves "B" and joins "A"...."A" will have 20 members and "B" will  have 10  and "A" will have twice as many members as "B"

 

 

 

cool cool cool

 Dec 17, 2016
 #2
avatar+870 
+5

That's right:

(and yeah, I still give those brownie pictures for right answers).

 Dec 17, 2016
 #3
avatar+129852 
0

Thanks for the brownie, EJ.......just in time for lunch !!!!

 

 

 

 

cool cool cool

 Dec 17, 2016

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