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Find the number of positive integers that are divisors of at least one of 1010,1212 , and 1515.

 Nov 3, 2019
 #1
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What are: 1010, 1212, 1515 ??? Are they supposed to be: 10, 12, 15?

 Nov 3, 2019
 #2
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It's 10 to the power of 10?

 

https://file.coffee/eAPmrxE_a.png

 Nov 3, 2019
 #3
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Divisors of 10^10 =2^10 x 5^10 = 11 x 11 =121

 

Divisors of 12^12 =2^24 x 3^12 = 25 x 13 =325

 

Divisors of 15^15 =3^15 x 5^15  = 16 x 16 =256

 

121 + 325 + 256 =702 divisors of all 3 numbers. However, I counted 34 as duplicates. If we remove these 34 duplicates, then we have: 702 - 34 =668 divisors of at least one of your 3 numbers (10^10, 12^12, 15^15).

 Nov 3, 2019

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