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Find the positive real value of t that satisfies \(|t+2i\sqrt{3}| |6-4i| = 26\)

 Mar 21, 2019

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 #1
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\(|t+2i\sqrt{3}||6-4i|=26\\ |t+2i\sqrt{3}|^2|6-4i|^2=676\\ (t^2+12)(36+16)=676\\ t^2 + 12 = 13\\ t^2 = 1\\ t = \pm 1\\ \text{The positive value of }t \text{ satisfying above is }1\)

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 Mar 21, 2019
 #1
avatar+6192 
+2
Best Answer

\(|t+2i\sqrt{3}||6-4i|=26\\ |t+2i\sqrt{3}|^2|6-4i|^2=676\\ (t^2+12)(36+16)=676\\ t^2 + 12 = 13\\ t^2 = 1\\ t = \pm 1\\ \text{The positive value of }t \text{ satisfying above is }1\)

Rom Mar 21, 2019

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