Find the positive real value of t that satisfies \(|t+2i\sqrt{3}| |6-4i| = 26\)
\(|t+2i\sqrt{3}||6-4i|=26\\ |t+2i\sqrt{3}|^2|6-4i|^2=676\\ (t^2+12)(36+16)=676\\ t^2 + 12 = 13\\ t^2 = 1\\ t = \pm 1\\ \text{The positive value of }t \text{ satisfying above is }1\)
