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avatar+467 

help please

 Nov 30, 2020
 #1
avatar+31533 
+1

If \(\log_9{(x-1)^2}=-1\) then \((x-1)^2=9^{-1}=\frac{1}{9}\)  so  \(x-1=\pm\frac{1}{3}\)

 

Can you take it from here?

 Nov 30, 2020
 #2
avatar+467 
0

Sorry but no

 Nov 30, 2020
 #3
avatar
0

x - 1 = - 1/3

x = - 1/3 +1

x = 2/3

 

x - 1 =1/3

x =1/3 + 1

x = 4/3

 Nov 30, 2020

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