+0

# Find the sum of all values of $x$ such that $\log_{3^2}(x-1)^2 = -1.$

0
64
3
+467

Nov 30, 2020

#1
+31533
+1

If $$\log_9{(x-1)^2}=-1$$ then $$(x-1)^2=9^{-1}=\frac{1}{9}$$  so  $$x-1=\pm\frac{1}{3}$$

Can you take it from here?

Nov 30, 2020
#2
+467
0

Sorry but no

Nov 30, 2020
#3
0

x - 1 = - 1/3

x = - 1/3 +1

x = 2/3

x - 1 =1/3

x =1/3 + 1

x = 4/3

Nov 30, 2020