+0

# Find the surface area and volume of a pentagonal prism with the given apothem length 12, side 6 and height 8.2

0
826
3

Find the surface area and volume of a pentagonal prism with the given apothem length 12, side 6 and height 8.2

Apr 29, 2015

#2
+101741
+5

I am going to assume it is a regular pentagonal prism.

a=12,      b=6     and   h=8.2

the area of the pentagon base = 5* (1/2)*6*12 = 180 thingys squared

Volume of pentagon  = 180*8.2 = 1476 thingys cubed

area of each rectangular side = 6*8.2= 49.2 thingys squared

surface area = $${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{49.2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{180}} = {\mathtt{606}}$$   thingys squared

Did I get the terminology correct TitaniumRome ?

Apr 29, 2015

#1
+3088
0

volume:

12*6*8.2=590.4 unit thingys cubed

surface area:

12*6*2+6*8.2*2+8.2*12*2=439.2 unit thingys squared

Volume: 590.4 Unit Thingys Cubed

Surface Area: 439.2 Unit Thingys Squared

Apr 29, 2015
#2
+101741
+5

I am going to assume it is a regular pentagonal prism.

a=12,      b=6     and   h=8.2

the area of the pentagon base = 5* (1/2)*6*12 = 180 thingys squared

Volume of pentagon  = 180*8.2 = 1476 thingys cubed

area of each rectangular side = 6*8.2= 49.2 thingys squared

surface area = $${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{49.2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{180}} = {\mathtt{606}}$$   thingys squared

Did I get the terminology correct TitaniumRome ?

Melody Apr 29, 2015
#3
+3088
0

indeed you have! congrats!

Apr 29, 2015