Find the units digit of 3777 or 3777=x(mod10)
1. gcd(10,3)=1|gcd=greatest common divisor2. φ(10)=4|φ=Euler functionφ(10)=10⋅(1−12)⋅(1−15)3. aφ(n)≡1(modn)|Euler′s Theorem, if gcd(a,n)=1 34≡1(mod10)|n=10a=33777(mod10)≡34⋅194+1(mod10)≡34⋅194⋅3(mod10)≡(34)194⋅3(mod10)≡(34⏟=1(mod10))194⋅3(mod10)≡1194⋅3(mod10)≡3(mod10)the Units digit of 3777 is 3
When looking for the units digit of 3n, look at the value of mod(n,4). When this is 0, the units digit is 1, when it is 1 the units digit is 3, when it is 2 the units digit is 9, when it is 3 the units digit is 7.
mod(777,4) = 1, so the units digit of 3777 is 3.
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Find the units digit of 3777 or 3777=x(mod10)
1. gcd(10,3)=1|gcd=greatest common divisor2. φ(10)=4|φ=Euler functionφ(10)=10⋅(1−12)⋅(1−15)3. aφ(n)≡1(modn)|Euler′s Theorem, if gcd(a,n)=1 34≡1(mod10)|n=10a=33777(mod10)≡34⋅194+1(mod10)≡34⋅194⋅3(mod10)≡(34)194⋅3(mod10)≡(34⏟=1(mod10))194⋅3(mod10)≡1194⋅3(mod10)≡3(mod10)the Units digit of 3777 is 3