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avatar+193 

Find the value of $a$ so that the system has no solutions.

\begin{align*}
y &= 11x+14 \\
2y-4 &= ax
\end{align*}

 Feb 14, 2021
 #1
avatar+112554 
+1

Hint:

It will have no solutions if the 2 lines are parallel.  So the gradients must be the same.

 Feb 14, 2021
 #2
avatar+193 
0

Thank you! I ended up getting 22.

clairepow  Feb 14, 2021
 #3
avatar+112554 
+1

Yes that'sright.

 

The number in front of the y is doubled so the number in front of the x must be doubled too.

(So long as they are both are on the same side of the equal sign that is fine.  )

 

y=11x+14

2y=ax+4

 

a=11*2=22

Melody  Feb 14, 2021

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