Find the value of $a$ so that the system has no solutions.
\begin{align*} y &= 11x+14 \\ 2y-4 &= ax \end{align*}
Hint:
It will have no solutions if the 2 lines are parallel. So the gradients must be the same.
Thank you! I ended up getting 22.
Yes that'sright.
The number in front of the y is doubled so the number in front of the x must be doubled too.
(So long as they are both are on the same side of the equal sign that is fine. )
y=11x+14
2y=ax+4
a=11*2=22
+193 
