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# Find the value of $a$ so that the system has no solutions.

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Find the value of $a$ so that the system has no solutions.

\begin{align*}
y &= 11x+14 \\
2y-4 &= ax
\end{align*}

Feb 14, 2021

#1
+113739
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Hint:

It will have no solutions if the 2 lines are parallel.  So the gradients must be the same.

Feb 14, 2021
#2
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Thank you! I ended up getting 22.

clairepow  Feb 14, 2021
#3
+113739
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Yes that'sright.

The number in front of the y is doubled so the number in front of the x must be doubled too.

(So long as they are both are on the same side of the equal sign that is fine.  )

y=11x+14

2y=ax+4

a=11*2=22

Melody  Feb 14, 2021