Find the value of $a$ so that the system has no solutions.

\begin{align*} y &= 11x+14 \\ 2y-4 &= ax \end{align*}

Hint:

It will have no solutions if the 2 lines are parallel. So the gradients must be the same.

Thank you! I ended up getting 22.

Yes that'sright.

The number in front of the y is doubled so the number in front of the x must be doubled too.

(So long as they are both are on the same side of the equal sign that is fine. )

y=11x+14

2y=ax+4

a=11*2=22