Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7,2), and is parallel to the graph of x + 3y = -5.

Guest Jun 27, 2021

#1**0 **

Line 1 = \(x + 3y = -5\)

Line 2 = \(Ax + By = 3\)

Rearrange Line 1 into slope intercept form,

Line 1 = \(y = -x/3 - 5\)

Because Line 2 has the same slope,

Line 2 = \(y = -x/3 + b\)

Multiply Line 2 by 3 on both sides and convert to standard form,

Line 2 = \(3y = -x + 3b\)

Line 2 = \(x + 3y = 3b\)

Line 2 must pass through (-7, 2), so we can plug in these values,

Line 2 = \(-1 = 3b\)

\(b = -1/3\)

Line 2 = \(x + 3y = -1\)

Multiply both sides by -3,

Line 2 = \(-3x + -9y = 3\)

B - A = -9 - (-3) = **-6**

Awesomeguy Jun 27, 2021