AIDS / A = SEER
This means the same as
S E E R
A
______
A I D S
Here's the logic of the solution
The last multiplication S x A = A implies that S = 1
The first multiplication R x A results in an ending value of 1
And....only the product 7 * 3 results in an ending "1"
Thus R = 3 and A = 7 or vice-versa
This means that EA + 2 = D
And EA + ?? = I
But there is no "carry" because SA could not = A if this were true
So... ?? = 0
Thus... EA < 10
But if A = 7 and EA < 10... guess that E could = 1
But this is impossible because S =1
And E cannot = 0 because the second multiplication (EA) would have to equal E if this was true
So.....A must equal 3
And E could only = 2
And the "carry" from R x A = 2
Which means that
2 + EA =
2 + 2(3) = 8 = D
And since there is no "carry" on the next multiplication ... I must = EA = 6
And R = 7
So we have that
1 2 2 7
3
_______
3 6 8 1
Or
AIDS / A = SEER
3681 / 3 = 1227