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Find the value of y so that the points (-5,10) and (3,y) lie on a line with slope -3/8

 Sep 10, 2014

Best Answer 

 #2
avatar+26387 
+5

Find the value of y so that the points (-5,10) and (3,y) lie on a line with slope -3/8

$$slope = \frac{\Delta y}{\Delta x} = \frac
{y-10}
{3-(-5)}
=
\frac
{y-10}
{8}
\\\\
\text{also slope } = -\frac{3}{8}$$

 

$$so\ we\ have \quad
\frac{y-10}{8} =
-\frac{3}{8} \qquad or\ \quad y-10=-3$$

 

the value of y = 7

 Sep 11, 2014
 #1
avatar+169 
+5

$$slope=\frac{y_a-y_b}{x_a-x_b}=\frac{y-10}{3--5}=\frac{y-10}{8}=-\frac{3}{8}$$

 

Now solve for y.

 

Good luck! :)

 Sep 10, 2014
 #2
avatar+26387 
+5
Best Answer

Find the value of y so that the points (-5,10) and (3,y) lie on a line with slope -3/8

$$slope = \frac{\Delta y}{\Delta x} = \frac
{y-10}
{3-(-5)}
=
\frac
{y-10}
{8}
\\\\
\text{also slope } = -\frac{3}{8}$$

 

$$so\ we\ have \quad
\frac{y-10}{8} =
-\frac{3}{8} \qquad or\ \quad y-10=-3$$

 

the value of y = 7

heureka Sep 11, 2014

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