Find the value of y. The line containing (1,-3) and (3,y) is parallel to the line containing (5,-6) and (9,y).
Here, since the lines are parallel, they have the same slope....so.....we just need to equate slopes and solve for y.......and we have......
[y + 3 ] / [3 - 1 ] = [y + 6] / [9 - 5] ...simplify....
[y + 3] / 2 = [y + 6] / 4 ....cross-multiply...
4[y + 3 ] = 2 [ y + 6]
4y + 12 = 2y = 12 .... subtract 12 from both sides and 2y from both sides....
2y = 0 ......divide by 2 on both sides.........
y = 0
Here, since the lines are parallel, they have the same slope....so.....we just need to equate slopes and solve for y.......and we have......
[y + 3 ] / [3 - 1 ] = [y + 6] / [9 - 5] ...simplify....
[y + 3] / 2 = [y + 6] / 4 ....cross-multiply...
4[y + 3 ] = 2 [ y + 6]
4y + 12 = 2y = 12 .... subtract 12 from both sides and 2y from both sides....
2y = 0 ......divide by 2 on both sides.........
y = 0