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Find the value of y. The line containing (1,-3) and (3,y) is parallel to the line containing (5,-6) and (9,y).

 Sep 30, 2014

Best Answer 

 #1
avatar+129514 
+5

Here, since the lines are parallel, they have the same slope....so.....we just need to equate slopes and solve for y.......and we have......

[y + 3 ] / [3 - 1 ]  =  [y + 6] / [9 - 5]         ...simplify....

[y + 3] / 2  = [y + 6] / 4                            ....cross-multiply...

4[y + 3 ] = 2 [ y + 6]

4y + 12 =  2y = 12             .... subtract 12 from both sides and 2y from both sides....

2y = 0                               ......divide by 2 on both sides.........

y = 0

 

  

 Sep 30, 2014
 #1
avatar+129514 
+5
Best Answer

Here, since the lines are parallel, they have the same slope....so.....we just need to equate slopes and solve for y.......and we have......

[y + 3 ] / [3 - 1 ]  =  [y + 6] / [9 - 5]         ...simplify....

[y + 3] / 2  = [y + 6] / 4                            ....cross-multiply...

4[y + 3 ] = 2 [ y + 6]

4y + 12 =  2y = 12             .... subtract 12 from both sides and 2y from both sides....

2y = 0                               ......divide by 2 on both sides.........

y = 0

 

  

CPhill Sep 30, 2014

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