Find the values of x and y that make Line 1 || Line 2 and Line 3 || Line 4.
We know that (5x+2y−25)+z=180.
Solving for z, we find that z=205−5x−2y
Using, alternate interior angles, we know that 2y+x+y+205−5x−2y=180
Simplifying, we find that 25=4x−y
Because we want L4 to be parallel to L3, the angles must be equal, meaning: 2y=4x+10
We now have a system of equations to solve: 2y=4x+10 and 25=4x−y
Solving, we find x=15, y=35
If L3 is parallel to L4, then, by corresponding angles
4x + 10 = 2y rearrange as
y = 2x + 5 (1)
And if L1 is parallel to L2, then, by the property of supplementary angles
5x + 2y - 25 + 2y + x + y = 180 rearrange as
6x + 5y = 205 (2)
Sub (1) into (2)
6x + 5 ( 2x + 5) = 205
6x + 10x + 25 = 205
16x = 180
x = 180 / 16 = 45/4 = 11.25
And
y = 2 (11.25) + 5 = 27.5