+0  
 
0
392
14
avatar+2448 

Idk how to solve this >.<

 Feb 12, 2018
 #1
avatar+250 
0

28 X 14 X 17

 

 

Your answer is 6664 

 Feb 12, 2018
 #3
avatar+2448 
0

I feel like it isn't that easy...and that is incorrect...

RainbowPanda  Feb 12, 2018
 #7
avatar+250 
+1

im sorry i hit the wrong button im also having a bad day and can´t think

penquino21  Feb 12, 2018
 #8
avatar+2448 
0

It's alright! Everyone makes mistakes. 

I hope your day becomes better~

RainbowPanda  Feb 12, 2018
 #10
avatar+250 
+1

ok thank you

penquino21  Feb 12, 2018
 #11
avatar+557 
+1

hope you day gets better as well

 

 

winkwinkwink

lynx7  Feb 12, 2018
 #4
avatar+557 
+4

volume of cuboid: 14*28*17

volume of cuboid: 6664cm^3

radius=7

area of semi circle=pi*r^2/2

area of semi circle=pi*7^2/2

area of semi circle=76.96902001cm^2

are of cross section*length

76.96902001cm^2*28=2155.13256cm^3

2155.13256cm^3+6664cm^3=8819.13256cm^3

 

 

winkwinkwink

 Feb 12, 2018
 #5
avatar+2448 
0

Thank you ^-^

RainbowPanda  Feb 12, 2018
 #6
avatar+557 
+1

no problem any time

 

 

winkwinkwink

lynx7  Feb 12, 2018
 #9
avatar+111331 
+4

The priism  is easy...it's just  W * L * H  = 14 * 28 * 17  = 6664 cm^3 (1)

 

For the half-cylinder...the volume is

 

 

(1/2 pi * r^2 * height

 

The "height" is the length of the  lunchbox   = 28 cm

We neeed to be careful with r  ...it  equals  14/ 2  = 7cm 

 

So  the volume of the half-cylinder is

 

(1/2) pi * (r^2) * h  =

 

(1/2) pi (7)^2 * 28  =  2155.13  cm^3    (2)

 

Add  (1) and (2)   =  8819.13 cm^3

 

 

cool cool cool

 Feb 12, 2018
 #12
avatar+250 
+2

thx cphill

penquino21  Feb 12, 2018
edited by penquino21  Feb 12, 2018
 #13
avatar+2448 
+1

Thank you ^-^

RainbowPanda  Feb 12, 2018
 #14
avatar+557 
+3

believe in yourself

 

 

winkwinkwink

lynx7  Feb 12, 2018

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