+0

# Find the volume.

0
392
14
+2448

Idk how to solve this >.<

Feb 12, 2018

#1
+250
0

28 X 14 X 17

Feb 12, 2018
#3
+2448
0

I feel like it isn't that easy...and that is incorrect...

RainbowPanda  Feb 12, 2018
#7
+250
+1

im sorry i hit the wrong button im also having a bad day and can´t think

penquino21  Feb 12, 2018
#8
+2448
0

It's alright! Everyone makes mistakes.

I hope your day becomes better~

RainbowPanda  Feb 12, 2018
#10
+250
+1

ok thank you

penquino21  Feb 12, 2018
#11
+557
+1

hope you day gets better as well

lynx7  Feb 12, 2018
#4
+557
+4

volume of cuboid: 14*28*17

volume of cuboid: 6664cm^3

area of semi circle=pi*r^2/2

area of semi circle=pi*7^2/2

area of semi circle=76.96902001cm^2

are of cross section*length

76.96902001cm^2*28=2155.13256cm^3

2155.13256cm^3+6664cm^3=8819.13256cm^3

Feb 12, 2018
#5
+2448
0

Thank you ^-^

RainbowPanda  Feb 12, 2018
#6
+557
+1

no problem any time

lynx7  Feb 12, 2018
#9
+111331
+4

The priism  is easy...it's just  W * L * H  = 14 * 28 * 17  = 6664 cm^3 (1)

For the half-cylinder...the volume is

(1/2 pi * r^2 * height

The "height" is the length of the  lunchbox   = 28 cm

We neeed to be careful with r  ...it  equals  14/ 2  = 7cm

So  the volume of the half-cylinder is

(1/2) pi * (r^2) * h  =

(1/2) pi (7)^2 * 28  =  2155.13  cm^3    (2)

Add  (1) and (2)   =  8819.13 cm^3

Feb 12, 2018
#12
+250
+2

thx cphill

penquino21  Feb 12, 2018
edited by penquino21  Feb 12, 2018
#13
+2448
+1

Thank you ^-^

RainbowPanda  Feb 12, 2018
#14
+557
+3

believe in yourself

lynx7  Feb 12, 2018