+209 y= e^x sinx
I tried it out but can't get the right answer.
I got y' = e^x(sinx)(cosx)
but can't figure out y''.
+129899 y= e^x sinx
Remember, Yura_chan.....we are using the Product Rule, here.....
y ' = e^xsinx + e^xcosx = e^x(sinx + cosx)
Use the Product and Chain Rules to find y "
y " = e^x(sinx + cosx) + e^x(sinx + cosx)^0 * ( cosx - sinx) =
e^x(sinx + cosx) + e^x (cosx - sinx) =
e^x [ sinx + cosx + cosx - sinx] =
e^x [2 cosx] =
2e^xcosx
