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y= e^x sinx

I tried it out but can't get the right answer. 
I got y' = e^x(sinx)(cosx)
but can't figure out y''.

 Feb 21, 2016
 #1
avatar+129852 
0

y= e^x sinx

 

Remember, Yura_chan.....we are using the Product Rule, here.....

 

y '  = e^xsinx + e^xcosx  =  e^x(sinx + cosx)

 

Use the Product and Chain Rules to find y "

 

y "   = e^x(sinx + cosx)   + e^x(sinx + cosx)^0 * ( cosx - sinx)   =

 

e^x(sinx + cosx) + e^x (cosx - sinx)  =

 

e^x [ sinx + cosx + cosx - sinx]  =

 

e^x [2 cosx] =

 

2e^xcosx

 

 

cool cool cool

 Feb 21, 2016
 #2
avatar+209 
0

Thank you so much!!

Yura_chan  Feb 22, 2016

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