find y(x)

Note that y(3)  would mean that  we put 3 into y and evaluate

So......this would imply that

y(x)    means that we are putting  x into  y and evaluating.......so we have

5(3t^2 - t + 1)^2  - (5/3)(3t^2 - t + 1)    - 2  

I used Wolfram Alpha   to  get

45 t^4 - 30 t^3 + 30 t^2 - (25 t)/3 + 4/3

I wondered about this one.....

If you multiply the value of x   by   5/3      you get    3 t^2 - 5/3 t + 5 /3

     now if you subtract 11/3

 you get     3 t^2 - 5/3t - 2

Soooooo.....    maybe ?    f(x) = 5/3 x - 11/3     ?????