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x=3t^2-t+1

y=5t^2-5t/3-2

y(x)-?

Help pls

 Mar 20, 2019
 #1
avatar+99441 
+1

Note that y(3)  would mean that  we put 3 into y and evaluate

 

So......this would imply that

 

y(x)    means that we are putting  x into  y and evaluating.......so we have

 

5(3t^2 - t + 1)^2  - (5/3)(3t^2 - t + 1)    - 2  

 

I used Wolfram Alpha   to  get

 

45 t^4 - 30 t^3 + 30 t^2 - (25 t)/3 + 4/3

 

 

cool cool cool

 Mar 20, 2019
 #2
avatar+17990 
+1

I wondered about this one.....

If you multiply the value of x   by   5/3      you get    3 t^2 - 5/3 t + 5 /3

     now if you subtract 11/3

 you get     3 t^2 - 5/3t - 2

 

Soooooo.....    maybe ?    f(x) = 5/3 x - 11/3     ?????

 Mar 20, 2019

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