Find the percentage of the area of a circle that is contained in an inscribed isosceles triangle, one of whose sides is the diameter of the circle
+128474 The diameter will be the longest side of the triangle......If we let this = 2r, the height of the triangle is r
So.... the area of the triangle is
(1/2)(2r) (r) = r^2
And the area of the circle is pi * r^2
So.....the ratio of the area is
r^2 / [ pi * r^2 ] =
1 / pi ≈ 31.8%
