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Find the percentage of the area of a circle that is contained in an inscribed isosceles triangle, one of whose sides is the diameter of the circle 

Guest Feb 7, 2018
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The diameter will be the longest side of the triangle......If we let this   = 2r, the height of the triangle is r

 

So.... the area of the triangle  is  

 

(1/2)(2r) (r)   =  r^2

 

And the area of the circle is pi * r^2

 

So.....the ratio of the area is  

 

r^2  / [ pi * r^2 ]  =

 

1 / pi    ≈   31.8%

 

 

cool cool cool

CPhill  Feb 7, 2018

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