Well, I know that a larger pyramid, an iceberg has:
Volume: 2469421500000 m^3
Base: 297700m x 165900m
height: 150m
Now 8/9 of the volume of this pyramid is underwater.
What is the height of the smaller pyramid, that is underwater
+178 *Read the question for 3 times and finally understood what it means*'
We know that the \(\frac{1}{9}\) part of the pyramid is above water, since the pyramid is three-dimensional, the volume of it is equal to the third power of its sides.
Now since we know that \(\frac{8}{9}\) of the volume is underwater, therefore the volume of the smaller pyramid which is above the water would be 8 times of the remaining pyramid which is underwater
The height of the smaller pyramid \(=x\), with the height of the remaining pyramid \(=150-x\)
\(x^3:(150-x)^3=1:8\)
Therefore \(150-x\) would be \(\sqrt[3]{8}=2\) times larger than \(x\):
\(150-x=2x\)
\(3x=150\)
\(x=50 (meters)\)
Done :D
(Time spent \(\approx\) 2 hours)
