Finding inverses

The idea is to get x by itself....then "swap" x and y...and for y, write the inverse 

y  =  [  ( x - 2 ) / 2 ]^(1/3)     cube both sides

y^3  = ( x - 2) / 2      multiply both sides by 2

2y^3  =  x  - 2    add 2 to  both sides

2y^3 + 2  = x      "swap"  x and  y

2x^3 + 2  = y      for y, write f^-1 (x)

f^-1(x)  = 2x^3 + 2

y  = -x^5      multiply through by -1

-y = x^5      take the 5th  root of both sides

[-y ]^(1/5)  =  x      "swap" x and y

[- x ] ^(1/5)  =  y     for y, write g^-1(x)

g^-1(x)  = (-x)^(1/5)