#1**+2 **

The idea is to get x by itself....then "swap" x and y...and for y, write the inverse

y = [ ( x - 2 ) / 2 ]^(1/3) cube both sides

y^3 = ( x - 2) / 2 multiply both sides by 2

2y^3 = x - 2 add 2 to both sides

2y^3 + 2 = x "swap" x and y

2x^3 + 2 = y for y, write f^{-1} (x)

f^{-1}(x) = 2x^3 + 2

CPhill Oct 29, 2018

#2**+1 **

That's what I got for #1 but I wrote it like 2+2x^3 dont think that matters though

RainbowPanda
Oct 29, 2018