+2448 Last ones that I need help with for today :)
\(f(x)=\sqrt[3]{x-1}\)
\(g(n)=2+2n^5\)
+129852 y = ( x - 1)^(1/3) cube both sides
y^3 = x - 1 add 1 to both sides
y^3 + 1 = x "swap" x an y
x^3 + 1 = y for y, write f-1(x)
f-1(x) = x^3 + 1
y = 2 + 2n^5 subtract 2 from both sides
y - 2 = 2n^5 divide both sides by 2
[ y - 2 ] / 2 = n^5 take the 5th root
( [ y - 2 ] / 2 ) ^(1/5) = n "swap" n and y
( [ n - 2 ] / 2 ) ^(1/5) = y for y, write g-1(n)
g-1(n) = ( [ n - 2 ] / 2 ) ^ (1/5) = 5√ [ ( n - 2) / 2 ]
