+0  
 
+1
38
1
avatar+2065 

Last ones that I need help with for today :)

\(f(x)=\sqrt[3]{x-1}\)

\(g(n)=2+2n^5\)

RainbowPanda  Oct 29, 2018
 #1
avatar+90995 
+2

y  =  ( x - 1)^(1/3)    cube both sides

y^3  = x  - 1      add 1 to both sides

y^3 + 1  =  x    "swap"  x an y

x^3 + 1  =  y      for y, write  f-1(x)

f-1(x)  = x^3 + 1

 

y  = 2 + 2n^5    subtract 2 from both sides

y - 2  =  2n^5     divide both sides by 2

[ y - 2 ] / 2  = n^5     take the 5th  root

( [ y - 2 ] / 2 ) ^(1/5)  = n       "swap"  n and y

( [ n - 2 ]  / 2 ) ^(1/5)  =  y     for y, write g-1(n)

g-1(n)  =  ( [ n - 2 ]  / 2 ) ^ (1/5)   =   5√ [  ( n - 2) / 2 ]

 

 

cool cool cool

CPhill  Oct 29, 2018

27 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.