with a mean of 73 and standard deviation of 8, what is the proportion of scores above 88?
+23252 Are you solving these problems by table or by calculator?
If you use a TE-84+, press: (2nd) (DISTR) 2:normalcdf
Then enter: normalcdf(88,9000,73,8)
The entries are lower bound, upper bound, mean, standard deviation.
I used 9000 for an upper bound, you can use any ridiciously large number.
If you need to solve this in a different manner, repost.
