+0

# Finding t

0
27
3

I'm kind of stuck. What do I do now?

-5t2 + 125t - 375 = 0

5t2 - 125t + 375 = 0

t2 - 25t + 75 = 0

May 22, 2020

#1
+30028
+2

Use the quadratic equation to get the two values of t:

$$t = {-(-25) \pm \sqrt{(-25)^2-4\times 75} \over 2}$$

I'll leave you to crunch the numbers.

Edited to replace x by t.

May 22, 2020
edited by Alan  May 22, 2020
#2
0

I'm not quite sure we've had this ? This looks overly complicated.

Guest May 22, 2020
#3
+30028
+1

It's the standard formula for solving quadratic equations (though I should have written "t = ..." not "x = ..."), which is often necessary when the quadratic equation doesn't factor nicely (as yours doesn't).

Alan  May 22, 2020