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I'm kind of stuck. What do I do now?

 

-5t2 + 125t - 375 = 0

5t2 - 125t + 375 = 0

t2 - 25t + 75 = 0

 May 22, 2020
 #1
avatar+30028 
+2

Use the quadratic equation to get the two values of t:

 

\(t = {-(-25) \pm \sqrt{(-25)^2-4\times 75} \over 2}\)

 

I'll leave you to crunch the numbers.

 

Edited to replace x by t.

 
 May 22, 2020
edited by Alan  May 22, 2020
 #2
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0

I'm not quite sure we've had this ? This looks overly complicated. 

 
Guest May 22, 2020
 #3
avatar+30028 
+1

It's the standard formula for solving quadratic equations (though I should have written "t = ..." not "x = ..."), which is often necessary when the quadratic equation doesn't factor nicely (as yours doesn't).

 
Alan  May 22, 2020

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