+0  
 
0
103
1
avatar

So here's the problem:

 

The expression for the 14th term of the geometric sequence \({x, x^3, x^5, ...}\) is....

 

and here are the possible solutions:

 

A  \({x^{13}}\)

B  \({x^{14}}\)

C  \({x^{27}}\)

D  \({x^{29}}\)

 

I'm completely stuck! :(

Guest Jun 9, 2018

Best Answer 

 #1
avatar+13048 
+1

Hmmmm?   Just march them on out.....you can do it...

 

1st       2nd      3rd     4th        5th .......14th

x          x^3      x^5      x^7       x^9

 

You probably can see a pattern......   multipy by 2    subtract 1

14 *2 = 28

Subtract 1 = 27

 

x^27      Not so really bad, huh?   Do you 'get it' ?    Cool!        Math on !

ElectricPavlov  Jun 9, 2018
 #1
avatar+13048 
+1
Best Answer

Hmmmm?   Just march them on out.....you can do it...

 

1st       2nd      3rd     4th        5th .......14th

x          x^3      x^5      x^7       x^9

 

You probably can see a pattern......   multipy by 2    subtract 1

14 *2 = 28

Subtract 1 = 27

 

x^27      Not so really bad, huh?   Do you 'get it' ?    Cool!        Math on !

ElectricPavlov  Jun 9, 2018

7 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.