Find the point of intersection for each pair of line
x+2y=4
3x+-2y=4
how would i solve this?
Rearrange both for either X or Y I think then you should be able to sub one into another
i.e. X = 4-2y
X = 4+2y/3
4-2y = 4+2y/3
12-6y = 4+2y
8 -6y = +2y
8 = 8y
y = 1
x+2y = 4
x+ 2(1) = 4
x + 2 = 4
x = 2
therefore point of intersection is (x=2, y=1)
I think.. someone might have to correct me on this though..
These are EACH the equation of a line. Where they INTERSECT x and y will satisfy BOTH of the equations....so just solve for x and y
From the FIRST equation x=4-2y
Sustitute THIS 'x' into the SECOND equation
3 (4-2y) -2y = 4
12-6y-2y =4
-8y = -8
y = 1 Since x=4-2y x=4-2 = 2
x,y = 2,1 You can sustitute these values into the TWO original equations to find this is true.
Rearrange both for either X or Y I think then you should be able to sub one into another
i.e. X = 4-2y
X = 4+2y/3
4-2y = 4+2y/3
12-6y = 4+2y
8 -6y = +2y
8 = 8y
y = 1
x+2y = 4
x+ 2(1) = 4
x + 2 = 4
x = 2
therefore point of intersection is (x=2, y=1)
I think.. someone might have to correct me on this though..
can someone help me?
During the past 10 years, the amount of money, M (in billions of dollars), spent in North America by car dealerships advertising their product can be modeled by the equation M = 0.15e^0.3t + 0.78. In what year was about $3 billion (M = 3) spent by car dealerships in advertising?
A. t = 9
B. t = 10
C. t = 8
D. t = 3
