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what are the zeros of this equation? x^3+1000

 Feb 19, 2016
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what are the zeros of this equation? x^3+1000

 

x3+1000=0x3=1000x=10

 

x=-10       is the only real solution but since it is a cubic there will be two more imaginary roots.

 

they well be     

 

x=cos(π2π3)+isin(π2π3)andx=cos(π+2π3)+isin((π+2π3)x=cos(π3)+isin(π3)andx=cos(5π3)+isin(5π3)x=12+32iandx=1232ix=(1+3)i2andx=(13)i2

 Feb 19, 2016

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