what are the zeros of this equation? x^3+1000
x3+1000=0x3=−1000x=−10
x=-10 is the only real solution but since it is a cubic there will be two more imaginary roots.
they well be
x=cos(π−2π3)+isin(π−2π3)andx=cos(π+2π3)+isin((π+2π3)x=cos(π3)+isin(π3)andx=cos(5π3)+isin(5π3)x=12+√32iandx=12−√32ix=(1+√3)i2andx=(1−√3)i2