For a cone, if the radius was quadrupled and the slant height was reduced to one sixth of its original size, what would be the formula to fi

$$Area=\pi rl+\pi r^2$$

$$\\
\frac{Area2}{Area1}=\frac{4r\frac{l}{6}+16r^2}{rl+r^2}\\\\
Area2 = Area1*\frac{2(l+24r)}{3(l+r)}$$

the surface area would be pie times ratio times the original slant height plus pie times ratio squared 2 if you do that you should find the answer hope this helped