For each problem below, solve algebraically. Then, use a table or graph to check your answer.
2500 = 1000 (1 + .028/12)^(12t) divide both sides by 1000
2500/1000 = (1 + .028/12)^(12t)
2.5 = (1 + .028/12)^(12t) take the og of both sides
log (2.5)= log (1 + .028/12)^(12t) and we can write
log(2.5) = (12t) log ( 1 + .028/12) divide both sides by 12 log (1 + .028/12)
log (2.5) / [ 12 log (1 + .028/12] = t ≈ 32. 8 years
Here's the graph : https://www.desmos.com/calculator/iihh2mezsg