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For each problem below, solve algebraically. Then, use a table or graph to check your answer.

 Apr 8, 2019
 #1
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2500 = 1000 (1 + .028/12)^(12t)     divide both sides by 1000

 

2500/1000 = (1 + .028/12)^(12t) 

 

2.5  =  (1 + .028/12)^(12t)     take the og of both sides

 

log (2.5)= log (1 + .028/12)^(12t)     and we can write

 

log(2.5) = (12t) log ( 1 + .028/12)       divide both sides by 12 log (1 + .028/12)

 

log (2.5) / [ 12 log (1 + .028/12] = t ≈  32. 8 years   

 

Here's the graph :  https://www.desmos.com/calculator/iihh2mezsg

 

 

cool cool cool

 Apr 8, 2019

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