For people in the future

There are 3 ways to stand so they do not have to stand next to each other

1001

1010

0101             the other two slots have 2 ways to be arranged     3 x 2 = 6 ways 

Guest answer is correct..... I neglected the fact that you could switch the two students around for a total of SIX ways they would not have to stand next to each other.....then the other two slots have two ways     soooo     6 x 2 = 12  ways

Thanx, Guest !

Give students names or initials:
A=Alice, B=Bob, C=Cathy, D=David
Suppose Alice and David do not want to stand next to each other, then you have the following arrangements: 4! / 2! = 12. A,D cannot stand next to each other
{A, B, C, D} | {A, B, D, C} | {A, C, B, D} | {A, C, D, B}  {B, A, C, D} | {B, D, C, A} | {C, A, B, D} | {C, D, B, A}  {D, B, A, C} | {D, B, C, A} | {D, C, A, B} | {D, C, B, A}