For positive integers $n$, let $f(n)$ return the smallest positive integer $k$ such that $\frac{1}{k}$ has exactly $n$ digits after the deci

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For positive integers $n$, let $f(n)$ return the smallest positive integer $k$ such that $\frac{1}{k}$ has exactly $n$ digits after the deci

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For positive integers n, let f(n) return the smallest positive integer k such that 1/k has exactly n digits after the decimal point. How many positive integer divisors does f(2010) have?

Guest Jan 11, 2021

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DewdropDancer · Answer 1 · 2021-01-11T03:37:17

The same problem was posted before! :) I don't exactly have a really good answer to this question, but I found one made by Guest, and he/she answered it really well, here's the link: https://web2.0calc.com/questions/number-theory_9.

Guest · Answer 2 · 2021-01-21T03:25:46

Thanks, but that answer is incorrect.

For positive integers $n$, let $f(n)$ return the smallest positive integer $k$ such that $\frac{1}{k}$ has exactly $n$ digits after the deci

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For positive integers $n$, let $f(n)$ return the smallest positive integer $k$ such that $\frac{1}{k}$ has exactly $n$ digits after the deci

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