+13 For the Function g(x)=x^2/3
Show that g'(0) does not exist...
also,If derivate at x=0 does not exist, this means the tangent line is a __________line.
+37152 g'(x) = 2/3 x^(2/3-1) = 2/3 x^(-1/3) = 2/3 * 1/ (x^1/3) = 2 / (3\(\sqrt[3]{x}\) )
if 'x' is ZERO it is undefined....or NOT ALLOWED (You cannot divide by zero)
this means that the tangent line is a hyperbolic or discontiguous line ?
