This is not an EQUATION...this is a RELATION.
to solve for x, you need to have an = 'something' to make it ann equation. Sorry
Solve for x:
(log(x^2 - 4 x + 1))/(log(10)) = 0
Multiply both sides by log(10):
log(x^2 - 4 x + 1) = 0
Cancel logarithms by taking exp of both sides:
x^2 - 4 x + 1 = 1
Subtract 1 from both sides:
x^2 - 4 x = 0
Factor x from the left hand side:
x (x - 4) = 0
Split into two equations:
x - 4 = 0 or x = 0
Add 4 to both sides:
Answer: |x = 4 or x = 0
Alright, I re-read your question.... for this to 'BE DEFINED' , the value of
x^2 - 4x+1 HAS to be POSITIVE (greater than 0-- because there is no logs of NEGATIVE numbers)
so
x^2 - 4x +1 > 0
Quadratic formula results in ZEROES at x = 2 +-sqrt3
If you graph this fxn you will see a parabola which is POSITIVE outside of these values and NEGATIVE between them
so 2+sqrt3 < x < 2-sqrt3
Huge thanks for your help!
Only thing:
wouldn't it be
2+sqrt3 "greater or equal to" x "lesser or equal to" 2-sqrt3
2+sqrt3 < x < 2-sqrt3
???