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014 (part 1 of 2) 10.0 points A(n) 97 kg clock initially at rest on a horizontal floor requires a(n) 698 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 526 N keeps it moving with a constant velocity. The acceleration of gravity is 9.81 m/s 2 . a) Find µs between the clock and the floor.

015 (part 2 of 2) 10.0 points b) Find µk between the clock and the floor.

 Dec 10, 2020
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Force norml to the floor    97 kg * 9.81 m/s^2      951.57  N 

 

friction forces = 698

698 = us 951.57                     us = .733

 

526 = uk 951.57                     uk = .552

=

 Dec 10, 2020

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