+0  
 
0
851
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avatar+2498 

what i need to know for solving that type of equations ?

 Feb 8, 2016

Best Answer 

 #1
avatar
+10

The answer is "A"= -1

 Feb 8, 2016
 #1
avatar
+10
Best Answer

The answer is "A"= -1

Guest Feb 8, 2016
 #2
avatar+129852 
+5

Solveit, we need to remember that    sin^2 (theta)  + cos^2(theta)  = 1

 

So we have :

 

[sin^4 (theta - cos^2(theta)]  / [ cos^2 (theta)  - sin^2(theta) ]          factor the numerator as a difference of squares, and we have

 

[ (sin^2 theta  + cos^2(theta)] [ sin^2(theta)  - cos^2(theta) ]  /  [ cos^2(theta) - sin^2(theta)]

 

 

1 * [ sin^2 (theta)  - cos^2(theta)] / [ cos^2 ( theta)  - sin^2(theta) ]       factor a  "-1"  out of the numerator

 

1 * (-1)[cos^2(theta) - sin^2(theta)] / [cos^2(theta)  - sin^2 (theta)]  =

 

1 * -1    =

 

-1

 

 

cool cool cool

 Feb 8, 2016
 #3
avatar+2498 
0

Thanks CPhill !

 Feb 9, 2016

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