Skylar had 3/5 as many coins as Ben. Ben gave 10 coins to Skylar so that they would each have the same amount. How many coins did the two friends have altogether?

Ajdabegano Jun 13, 2022

#1**0 **

Suppose Ben had \(b\) coins originally. Then Skylar has \(3b/5\) coins (also originally).

Since after Ben gives Skylar ten coins they each have the same amount, we can get the equation

\(b-10=3b/5+10\)

Solving, we have \(b=50\), so then Skylar had \(30\) coins. Therefore, the two friends had \(\boxed{80}\) coins altogether.

RainbowSquirrel53 Jun 13, 2022