John bought some pens and pencils. After he sold 1/3 of the pens and 3/5 of the pencils, he had twice as many pens as pencils left. Given John bought 50 more pens than pencils, how many pens and pencils did John have altogether?
x = pens
y = pencils
(2/3)x = 2* (2/5)y
x = 50 + y
(2/3)(50 + y) = 2*(2/5)y
100/3 + 2y/3 = 4y/5
500 + 10y = 12y
y = 250
x = 300
550.
+1693 John bought some pens and pencils. After he sold 1/3 of the pens and 3/5 of the pencils, he had twice as many pens as pencils left. Given John bought 50 more pens than pencils, how many pens and pencils did John have altogether?
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John bought 50+x pens and x pencils.
(50 + x - 1/3(50 + x)) / (x + 3/5x) = 2
x = 250
50+x + x = 550
