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# Fractions

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John bought some pens and pencils. After he sold 1/3 of the pens and 3/5 of the pencils, he had twice as many pens as pencils left. Given John bought 50 more pens than pencils, how many pens and pencils did John have altogether?

Aug 13, 2021

#1
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x = pens

y = pencils

(2/3)x = 2* (2/5)y

x = 50 + y

(2/3)(50 + y) = 2*(2/5)y

100/3 + 2y/3 = 4y/5

500 + 10y = 12y

y = 250

x = 300

550.

Aug 13, 2021
#2
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Guest Aug 13, 2021
#4
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You too! civonamzuk  Aug 14, 2021
#6
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My name is Allygator0777

Guest Aug 14, 2021
#3
+1

John bought some pens and pencils. After he sold 1/3 of the pens and 3/5 of the pencils, he had twice as many pens as pencils left. Given John bought 50 more pens than pencils, how many pens and pencils did John have altogether?

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John bought 50+x pens and x pencils.

(50 + x - 1/3(50 + x)) / (x + 3/5x) = 2

x = 250

50+x + x = 550 Aug 14, 2021
#5
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corrections:

(50 + x - 1/3(50 + x)) / (x - 3/5x) = 2 civonamzuk  Aug 14, 2021