John bought some pens and pencils. After he sold 1/3 of the pens and 3/5 of the pencils, he had twice as many pens as pencils left. Given John bought 50 more pens than pencils, how many pens and pencils did John have altogether?

Guest Aug 13, 2021

#1**+1 **

x = pens

y = pencils

(2/3)x = 2* (2/5)y

x = 50 + y

(2/3)(50 + y) = 2*(2/5)y

100/3 + 2y/3 = 4y/5

500 + 10y = 12y

y = 250

x = 300

**550**.

Guest Aug 13, 2021

#3**+1 **

John bought some pens and pencils. After he sold 1/3 of the pens and 3/5 of the pencils, he had twice as many pens as pencils left. Given John bought 50 more pens than pencils, how many pens and pencils did John have altogether?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

John bought **50+x** pens and **x** pencils.

(50 + x - 1/3(50 + x)) / (x + 3/5x) = 2

x = 250

50+x + x = 550

civonamzuk Aug 14, 2021