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# Fractions

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Hunter 1/4 of his money and an additional $7 to Shenese. He had$23 left. How much did Hunter have at first?

Apr 27, 2021

#1
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The question isn't very clear but I'll answer based on my understanding. So Hunter spent 1/4 of his money and an additional 7 dollars for something else. He has 23 dollars left. And you want to find how much he had in the beginning. If this is the question, the answer's below.

You should make an equation with the variable x for how much he had at first. So it would be $$1/4x + 7 = 23$$

Solving for the equation, you get

 $$x=64$$
Apr 27, 2021
#3
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I'm sorry. I don't understand. Can you please clarify what you mean by 40? Did I understand the question wrong?

weebh4.1zh0  Apr 27, 2021
#4
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Yea the answer is 40 but I don't know how to get 40

Guest Apr 27, 2021
#7
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Can you type the full question? Because maybe I'll understand it better if I get the full question

weebh4.1zh0  Apr 27, 2021
edited by weebh4.1zh0  Apr 27, 2021
#8
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That is the full question.

Guest Apr 27, 2021
#9
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Well then I'm sorry I can't help you. I really don't understand how the answer is 40 unless I understand the question incorrectly

weebh4.1zh0  Apr 27, 2021
#5
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did you type in the full question? I think were some parts you didnt add.

Apr 27, 2021
#6
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No that's why the question says

Guest Apr 27, 2021
#11
+1

If I'm not mistaken, this question is saying that Hunter gave a quarter of his money and an additional 7 dollars to Shenese.
Let x represent the amount of money Hunter had originally

$$x - \frac{1}{4}x - 7 = 23$$

$$\frac{3}{4}x = 30$$

$$3x = 120$$

$$x = 40$$

Hopefully it's correct?

Apr 27, 2021
#13
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Ohh thank you for clarifying that -- I wrote my equation wrong 😅

weebh4.1zh0  Apr 27, 2021
#14
+1

x - (x/4 + 7) = 23

x = 40

Hunter had \$40 Apr 27, 2021