1/3 of Milo's money was 4/5 of Alan's money. If Milo gave $18 to Alan and he returned $4 to him a few days later, then both of them would have an equal amount of money left. How much did Milo have at first?
Lets Assume Milo have at first
X
Money and Alan have at First Y money
1/3 X = 4/5Y
So Y = 5/12X
X-18 +4 = Y +18 -4
X-14 = Y + 14
Now we will input Y Value in the equation
X- 14 = 5/12X + 14
7/12X =28
X = 28*12/7
X = 336/7
X = 48
+36 
