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# Fractios

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Select the exclusion that fits best with this problem.

a^3-b^3/a^3b^3+a^2b^4+ab^5=

x,y,z=0

x=0

1+y+y^2, y=0, 1-y=0

2x-1=0, 4x^2+2x+1=0

a, b= 0, a^2+ab+b^2=0

May 1, 2023

#1
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x,y,z=0

Step-by-step explanation:

For this case we have the following expression:
3x ^ 2y ^ 2-6xz / 6x ^ 2yz
From here, we must exclude all values that make the denominator equal to zero.
We have then:
6x ^ 2yz = 0
Therefore, the results are:
x = 0
y = 0
z = 0
The exclusion that fits best with this problem is:
x, y, z = 0

May 1, 2023
#2
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I don't get how you got that answer. The variables are A and B.

Guest May 1, 2023
#3
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Well ' I ' concluded because from looking at the problem:

a^3-b^3 / a^3b^3+a^2b^4+ab^5 it is a fraction correct?

And from the fraction the calue of variable of a expression are excluded for which expression does not exist, where denominator is going to be zero those value going to be excluded. So making the denominator ( NOT ' 0 ' ) so like in The question best fits the problem:

I need to find point where it become zero we put 6x²yz equal to 0

6x²yz = 0

Making the new problem of:x² = 0  or y = 0 or z = 0

x² = 0  or y = 0 or z = 0

and concealing the problem making option a correct.

acyclics  May 1, 2023