Select the exclusion that fits best with this problem.
1+y+y^2, y=0, 1-y=0
a, b= 0, a^2+ab+b^2=0
For this case we have the following expression:
3x ^ 2y ^ 2-6xz / 6x ^ 2yz
From here, we must exclude all values that make the denominator equal to zero.
We have then:
6x ^ 2yz = 0
Therefore, the results are:
x = 0
y = 0
z = 0
The exclusion that fits best with this problem is:
x, y, z = 0
Well ' I ' concluded because from looking at the problem:
a^3-b^3 / a^3b^3+a^2b^4+ab^5 it is a fraction correct?
And from the fraction the calue of variable of a expression are excluded for which expression does not exist, where denominator is going to be zero those value going to be excluded. So making the denominator ( NOT ' 0 ' ) so like in The question best fits the problem:
I need to find point where it become zero we put 6x²yz equal to 0
6x²yz = 0
Making the new problem of:x² = 0 or y = 0 or z = 0
x² = 0 or y = 0 or z = 0
and concealing the problem making option a correct.