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(From my 11th/12th grade math homework) Can you give me an explanation to why ba^(x+Δx)/ba^x = ba^Δx? 

 Sep 17, 2014

Best Answer 

 #1
avatar+33659 
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I assume ba is a single variable name, not b*a.

 

From the laws of indices (powers) we have zm*zn = zm+n

For example think of 23*22 = 2*2*2*2*2 = 25 = 23+2

 

In your case  bax+Δx = bax*baΔx, so if you divide this by bax you are left with baΔx

 Sep 17, 2014
 #1
avatar+33659 
+5
Best Answer

I assume ba is a single variable name, not b*a.

 

From the laws of indices (powers) we have zm*zn = zm+n

For example think of 23*22 = 2*2*2*2*2 = 25 = 23+2

 

In your case  bax+Δx = bax*baΔx, so if you divide this by bax you are left with baΔx

Alan Sep 17, 2014

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